Calculation of Bar Bending Scheduling & Details

The purpose of bar bending schedule is to convey the design intent of steel reinforcement to the fabricator and execution team to measure the weight of each size of steel.

It is an extensive list that defines the location, mark, type, size, length, number and bending details of each bar in a reinforcement drawing of a structure.

The method of listing is known as scheduling.

Bar bending schedule contains various items like member identification (beam, slab, column etc.), bar mark (top, bottom, binder etc.), shape of bending, diameter of bar, length of each bar, total numbers of bars, total length, weight.

Reinforcement bar details: The standard/maximum length available is 12 meter. It can be adjusted from 5.5 meters of length based on the usage.

Diameter and unit weight of steel: The lowest diameter of reinforcement accessible is 6 mm and the highest diameter accessible is 40 mm.

A general exists to measure the unit weight of steel is (D^2/162), where D is the diameter of steel.

Shape of bending: The shape bar that normally appears as a straight bar and available in a length of 12 meter should be cut and bent in according to the need of structural drawings.

Also Read: How to use BarBeQue software for Reinforcement Bar Bending Schedules for RCC Work

Bar mark & no’s of bars
For every structural member every bar contains a mark or a designation (top, bottom, extra, stirrups).
For members like beams, columns and walls, bars can be measured by hand from the structural drawings.

For members similar to slab, it can be computed as following :-
No. of bars = (width of concrete – 2*clear cover)/ c/c spacing among bars.

Length of each bar – It is measured from the provided structural drawings by adding the development length (if necessary), anchorage length, deduction of bends etc. Bend deduction is done on the basis of IS-2502 code.

Total weight of bars – It is measured by simply applying the formula
Wt. of a bar = (No. of bars*length*unit weight) kg.

How calculation is done

1. No of bars = (length/spacing) + 1

2. Cutting length
for 45 degrees = total length – 1(dia. of bar)(no. of bends)
for 90 degrees = total length – 2(dia. Of bar)(no. of bends)

3. For stirrups
90 degrees hook - Length of stirrups = (2A + 2B) + 20 (dia.)

135 degrees hook
Length of stirrups = (2A + 2B) + 24 (dia.)